help: new sine with shifted phase expression

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ragv
Posts: 2
Joined: Thu Dec 28, 2017 5:24 pm

help: new sine with shifted phase expression

Post by ragv » Thu Dec 28, 2017 5:46 pm

This expression: sin(2*pi*f*t), I want it to create a sine with a few degrees shifted phase. It might take a long time till I figure it out myself.

DougDbug
Posts: 2034
Joined: Wed Feb 16, 2005 3:33 pm
Location: Silicon Valley

Re: help: new sine with shifted phase expression

Post by DougDbug » Thu Dec 28, 2017 10:02 pm

It took me a couple of minutes, but here you go:

t is time in seconds so for example, at 1kHz 360 degrees is 0.001 seconds or 0.00025 is a 90 degree shift:
sin(2*pi*f*(t+0.00025))

Or in terms of frequency, time = (angle/360)/f

Finally, using the User Constant x for angle we get :
sin(2*pi*f*(t+(x/360)/f))

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